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Print all available sensors name

8848512
over 2 years ago

Hi,

I'm a Swift developer but newbie with Monkey C

How can I get all available sensors of Garmin watch and print the name?
(make a loop of sensors array and print the name of sensor)

Thank you!  

  • over 2 years ago in reply to Ultra

    What I do wrong? Why I get "Cannot find symbol ':size' on type ", Is availableSensors an array or am I wrong?

    function onShow() as Void {
    var currentTime = System.getClockTime();
    System.println(currentTime.hour.format("%d")+":"+currentTime.min.format("%02d"));


    var availableSensors = Sensor.getRegisteredSensors(null);
    for (var i = 0; i < availableSensors.size(); i++) {
    System.println(availableSensors[i].Sensor.name);

    }
  • over 2 years ago in reply to 8848512

    getRegisteredSensors() returns an iterator, not an array. Note that even though the API functions which return an iterator are not documented to return null, in practice they can return null (I think, based on what others have posted in the forums).

    e.g.

    var sensorIterator = Sensor.getRegisteredSensors(null);
if (sensorIterator != null) {
    while (true) {
        var sensor = sensorIterator.next();
        if (sensor == null) {
            break;
        }
        System.println(sensor.name);
    }
}

    Yes it's awkward.

    Personally I would probably go with something like this:

    var sensorIterator = Sensor.getRegisteredSensors(null);
var sensor = sensorIterator != null ? sensorIterator.next() : null;
while (sensor != null) {
    System.println(sensor.name);
    sensor = sensorIterator.next();
}

  • over 2 years ago in reply to FlowState

    Thank you, It's so different from Swift in Swift things are more easy and friendly.
    I still don't know why my sensor var is always null I need to check it

    var sensorIterator = Sensor.getRegisteredSensors(null);

while (sensorIterator != null) {
     var sensor = sensorIterator.next();

         if (sensor == null) {
            System.println("No more sensors");
             break;
        }

      System.println(sensor.name);
}
  • over 2 years ago in reply to 8848512
    8848512 said:
    Thank you, It's so different from Swift in Swift things are more easy and friendly.

    Yeah...

    8848512 said:
    I still don't know why my sensor var is always null I need to check it

    Are you running this in the sim or a real device? I'm not sure if the sim will ever show any registered sensors.