How to load a another file resources.xml with program

Hi dev men

In directory resources there is the file resources.xml

in this example for a full version
<setting propertyKey="@Properties.VZ1" title="@Strings.ChoixTitleV1" prompt="@Strings.ChoixPrompt">
<settingConfig type="list">
<listEntry value="0">@Strings.elapsedDistance</listEntry>
<listEntry value="1">@Strings.altitude</listEntry>
<listEntry value="2">@Strings.dplus</listEntry>
<listEntry value="3">@Strings.dmoins</listEntry>
<listEntry value="4">@Strings.speed</listEntry>
<listEntry value="5">@Strings.speed15</listEntry>
<listEntry value="6">@Strings.avgspeed</listEntry>


</settingConfig>
</setting>


in this i would like give a different resource.xml if you have a full version vs a free version

example for a free version
<setting propertyKey="@Properties.VZ1" title="@Strings.ChoixTitleV1" prompt="@Strings.ChoixPrompt">
<settingConfig type="list">
<listEntry value="0">@Strings.elapsedDistance</listEntry>
<listEntry value="1">@Strings.altitude</listEntry>


</settingConfig>
</setting>

Is it possible with program to say

if (free version) load resources.xml for free version
else load resources.xml for full version

Perhaps with rez module
It's possible for a type of watch, is it possible with program

Thank's