Is it possible to use a php page output within a widget?

In the makeWebRequest, use HTTP_RESPONSE_CONTENT_TYPE_TEXT_PLAIN

Thanks, Jim I'm in way over my head but determined. Can you give me a clue as to how I then split that result down to the component parts?

So, your IQ program is getting data from a page written in PHP?

Have the page output JSON. It's easy to do. And it makes the IQ side easier. 

Yep, thats essentially it

widget will call 1 api passing geo location from watch (or fixed location) this will get an ID

2nd API will use the ID to obtain more information which will then be used to call a PHP page passing parameters and returning my final result. 

Thats the theory, 

So within the PHP output, I just need to wrap the array syntax for the JSON output, set the header and dump out the result?

like this : http://0-21.co.uk/tide4.php

Yes, that's it.

Use the following at the top of your PHP code (before creating any output):

header('Content-Type: application/json; charset=utf-8');

In addition to the header command, check out the json_encode command.  If you store your expected JSON in an associative array, you can use the json_encode method to format the contents of the array in JSON output.  It saves you from having to manually build the JSON and possibly making a error in the format.  I use both the header command followed by the json_encode command to support a couple watch apps I developed that talk to a PHP server API I developed as a proof of concept services.

I triedthat one but getan escaletd result

echo json_encode($reult, JSON_PRETTY_PRINT);

or

echo json_encode($ripped_piece, JSON_UNESCAPED_SLASHES);

like this : http://0-21.co.uk/tide4.php

I presume this is due to me already formatting the JSON? It passes testing at https://jsonlint.com/

thanks for the help, really appreciated it!

You don't need to do any formatting on the array.

I build my array using the following method.

$result['key1']="string1";

$result['key2']=value;

Then I use the following to display the result.

echo json_encode($result);

I don't try to force any specific output since I am using an associative array already forces the JSON to output and an object.

OK, sounds like I have all the components, now just need to put them all together. 

Thanks for the guidance, I'm sure I'll need more as I go ;-)