Week of year

Yes, you have to calculate the value though. It isn't that difficult. I can post code.

1784

Hello TRAVIS.VITEK,

That would be very happy if you could give me an example.
So I an approach as it can be done.
Thank you very much for your efforts.

greeting
Heiko

Sent code via PM.

Yes, you have to calculate the value though. It isn't that difficult. I can post code.

I could really like a copy of this code too.

Thanks a lot in advance

Hi Travis i am interresting in the code too

Thank's

Why the conspiracy all of a sudden?

using Toybox.Time.Gregorian as Greg;
...
var dateInfo = Greg.info(Time.now(), Time.FORMAT_SHORT);
var dayInAYear = (Time.now().value() - Greg.moment({:year => dateInfo.year, :month => 1, :day => 1, :hour => 0, :minute => 0, :second => 0}).value()) / 86400;
Sys.println("today is "+ dayInAYear +"th day of the year, "+ (dayInAYear / 7 + 1) +"th week");
...


Is there something particular I'm missing?

I guess it could vary based on what "week of year" is defined as for an app.

For example, is the first week from 1/1 to the next sunday or monday (based on a setting like "start of week"), and each week counted after that is from sunday to saturday (or monday to sunday based on the "start of week")

Or is a "week" from whatever day 1/1 is on to the next one?

Why the conspiracy all of a sudden?

using Toybox.Time.Gregorian as Greg;
...
var dateInfo = Greg.info(Time.now(), Time.FORMAT_SHORT);
var dayInAYear = (Time.now().value() - Greg.moment({:year => dateInfo.year, :month => 1, :day => 1, :hour => 0, :minute => 0, :second => 0}).value()) / 86400;
Sys.println("today is "+ dayInAYear +"th day of the year, "+ (dayInAYear / 7 + 1) +"th week");
...


Is there something particular I'm missing?

This is a good starting point, but the weeknumber is not calculated correct.

It seems a bit complicated to calculate, especially for the years containing 53 weeks.

Anybody have a final and complete solution so I don't have to re-invent the wheel

Thanks in advance
https://en.wikipedia.org/wiki/Week#Week_numbering

Well, I never really did these calculations before since in Android Java there's always trustworthy Calendar.getInstance.get(Calendar. WEEK_OF_YEAR), but I do like to reinvent wheels if it seems interesting enough 8)) According to provided Wiki, and I must admit, that this info was new to me, I'd change my code to this (checked to compile and run in simulator):

...
Sys.println("today is "+ getWeekNumber(Time.now()) +"th week");
Sys.println("01.01.2016 belongs to "+ getWeekNumber(Greg.moment({:year => 2016, :month => 1, :day => 1, :hour => 0, :minute => 0, :second => 0})) +" week");
Sys.println("03.01.2016 belongs to "+ getWeekNumber(Greg.moment({:year => 2016, :month => 1, :day => 3, :hour => 0, :minute => 0, :second => 0})) +" week");
Sys.println("04.01.2016 belongs to "+ getWeekNumber(Greg.moment({:year => 2016, :month => 1, :day => 4, :hour => 0, :minute => 0, :second => 0})) +" week");
...
function getWeekNumber(moment) {
var dateInfo = Greg.info(moment, Time.FORMAT_SHORT);
var firstDayOfTheYear = Greg.moment({:year => dateInfo.year, :month => 1, :day => 1, :hour => 0, :minute => 0, :second => 0});
var dayInAYear = (moment.value() - firstDayOfTheYear.value()) / 86400;
var weekNumber = dayInAYear / 7;
var firstDayDoW = Greg.info(firstDayOfTheYear, Time.FORMAT_SHORT).day_of_week;
// var lastDayOfFirstWeek = 9 - firstDayDoW; //my bad: Friday = 6, Satudray = 7, Sunday = 1
var lastDayOfFirstWeek = (9 - firstDayDoW) % 7;
return weekNumber == 0 && (firstDayDoW == 1 || firstDayDoW >= 6) && dateInfo.day <= lastDayOfFirstWeek ?
getWeekNumber(Greg.moment({:year => dateInfo.year - 1, :month => 12, :day => 31, :hour => 0, :minute => 0, :second => 0})) :
(weekNumber + 1);
}