using Activity.getActivityInfo() without importing Activity?

Hi. I just noticed an oversight on my part - I am using Activity.getActivityInfo() in the code without importing Activity (using Toybox.Activity;)

No compiler issues, the code works fine.

is this a global object available without importing, or am I missing something?

Thanks!

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jim_m_58 over 5 years ago +1

This won't cause an error all the time, but in some cases a warning.

Nothing strange here.
Travis.ConnectIQ over 5 years ago +1

This is because the runtime search algorithm is kinda wonky. I don't recall the exact details, but this should get the gist across...

Imagine that you have a class MyView that inherits from WatchUi…

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jim_m_58 over 5 years ago

This won't cause an error all the time, but in some cases a warning.

Nothing strange here.

Joe Berger over 5 years ago in reply to jim_m_58

Thanks, Jim!

Travis.ConnectIQ over 5 years ago

This is because the runtime search algorithm is kinda wonky. I don't recall the exact details, but this should get the gist across...

Imagine that you have a class MyView that inherits from WatchUi.View and references the Activity module. When the virtual machine encounters a reference to they symbol Activity, it looks in the current class ($.MyView) first, then it looks up the base class chain recursively ($.Toybox.WatchUi.View, then $.Toybox.Lang.Object). If the symbol isn't found, the search will look in the containing modules of the current class and each base class ($, then $.Toybox.WatchUi, then $.Toybox, then $.Toybox.Lang). When it is searching $.Toybox it will find $.Toybox.Activity.

I'm fairly certain that if you make a global function that references something from Activity, it will fail with an undefined symbol error. The search would only look in $, and there is no $.Activity symbol, so the lookup fails.

Joe Berger over 5 years ago in reply to Travis.ConnectIQ

Thanks, Travis. This is good info