Looking to 3D print an external batter for my Edge 530. If i use the usb port I would need 5v. That would require two 18650 lithium ion cells in series giving me 7.2-8.4v and a voltage reg to get a constant 5v. How about the pinouts on the bottom mount? I presume the unit is actually 3.6v nominal to a max of 4.2v. Could I use a single 18650 at 3.6 to 4.2 direct to the bottom pins? Didn't really want to take my 530 apart, so I thought I'd ask : ) It would also me 1/3 the size of two cells and a reg.